Aim

To prepare a sample of 1-Bromobutane for use in a laboratory

Background Chemistry

One way of preparing 1-Bromobutane is to start with Butan-1-ol and replace the -OH group on it with a -Br group by means of a substitution reaction. The reaction requires a supply of HBr which has to be produced ‘on-site’ as bottled HBr is unavailable as a reagent. The reaction can be represented by the equation:

CH3CH2CH2CH2OH + HBr               >     CH3CH2CH2CH2Br + H2O

This is a nucleophilic substitution reaction, and the products are impure, and various stages of purification is required before a sample of reasonable purity can be obtained.

theory

(1) Sodium Bromide reacts with Sulphuric Acid to form Hydrogen Bromide and Sodium Hydrogen Sulphate.

NaBr + H2SO4               >     HBr + NaHSO4

(2) Hydrogen Bromide is oxidised to Bromine molecules as concentrated Sulphuric Acid is a very good oxidising agent. The Sulphuric Acid reacts to form Sulphur Dioxide gas.

HBr + H2SO4               >     Br2 + 2SO2 (g)

(3) Hydrogen Bromide dissociates and the Bromide ion from it attacks the Carbon atom with the -OH function group in Butan-1-ol and displaces the -OH function group forming a Bromo function group and a hydroxide ion, which then associates itself with another H+ ion to form water.

CH3CH2CH2CH2OH + Br-               >     CH3CH2CH2CH2Br + OH-

(4) A molecule of Sulphuric Acid attacks the lone pair on an -OH function group, releasing a molecule of water, and a mixture of Butoxybutane and But-1-ene is formed, along with the regenerated Sulphuric Acid.

CH3CH2CH2CH2OH + H2SO4               >     CH3CH2CH=CH2 + H2O + H2SO4

or

2 CH3CH2CH2CH2OH + H2SO4               >     CH3(CH2)3O(CH2)3CH3 + H2O + H2SO4