Aim
To prepare a sample of 1-Bromobutane for use in a laboratory |
Background Chemistry
One way of preparing 1-Bromobutane is to start with Butan-1-ol
and replace the -OH group on it with a -Br group by means of a substitution
reaction. The reaction requires a supply of HBr which has to be
produced ‘on-site’ as bottled HBr is unavailable as
a reagent. The reaction can be represented by the equation:
CH3CH2CH2CH2OH + HBr > CH3CH2CH2CH2Br
+ H2O
This is a nucleophilic substitution reaction, and the products
are impure, and various stages of purification is required before
a sample of reasonable purity can be obtained. |
theory
(1) Sodium Bromide reacts with Sulphuric Acid to form Hydrogen
Bromide and Sodium Hydrogen Sulphate.
NaBr + H2SO4 > HBr
+ NaHSO4
(2) Hydrogen Bromide is oxidised to Bromine molecules as concentrated
Sulphuric Acid is a very good oxidising agent. The Sulphuric Acid
reacts to form Sulphur Dioxide gas.
HBr + H2SO4 > Br2
+ 2SO2 (g)
(3) Hydrogen Bromide dissociates and the Bromide ion from it attacks
the Carbon atom with the -OH function group in Butan-1-ol and displaces
the -OH function group forming a Bromo function group and a hydroxide
ion, which then associates itself with another H+ ion to form water.
CH3CH2CH2CH2OH + Br- > CH3CH2CH2CH2Br
+ OH-
(4) A molecule of Sulphuric Acid attacks the lone pair on an -OH
function group, releasing a molecule of water, and a mixture of
Butoxybutane and But-1-ene is formed, along with the regenerated
Sulphuric Acid.
CH3CH2CH2CH2OH + H2SO4 > CH3CH2CH=CH2
+ H2O + H2SO4
or
2 CH3CH2CH2CH2OH
+ H2SO4 > CH3(CH2)3O(CH2)3CH3
+ H2O + H2SO4 |